| Sunday, May 20, 2007 |
| Squaring a 2-digit number ending in 9 |
1. Choose a 2-digit number ending in 9. 2. The last digit of the answer is always 1: _ _ _ 1 3. Multiply the first digit by 8 and add 8 (keep the carry): _ _ X _ 4. Multiply the first digit by the next consecutive number and add the carry: the product is the first two digits: XX _ _.
Example:
1. If the number is 39: 2. The last digit of the answer is 1: _ _ _ 1 3. Multiply the first digit (3) by 8 and add 8 (keep the carry): 8 × 3 = 24, 24 + 8 = 32; the next digit of the answer is 2 (keep carry 3): _ _ 2 1 4. Multiply the first digit (3) by the next number (4) and add the carry (3): 3 × 4 = 12, 12 + 3 = 15 (the first two digits): 1 5 _ _ 5. So 39 × 39 = 1521.
See the pattern?
1. For 79 × 79 2. The last digit of the answer is 1: _ _ _ 1 3. Multiply the first digit (7) by 8 and add 8 (keep the carry): 8 × 7 = 56, 56 + 8 = 64; the next digit of the answer is 4 (keep carry 6): _ _ 4 1 4. Multiply the first digit (7) by the next number (8) and add the carry (6): 7 × 8 = 56, 56 + 6 = 62 (the first two digits): 6 2 _ _ 5. So 79 × 79 = 6241.
Practice other examples using this pattern, and in no time you'll be able to give these squares faster than someone using a calculator. |
posted by marhadi @ 6:23 AM  |
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