| Sunday, May 20, 2007 |
| Squaring a 2-digit number ending in 8 |
1. Choose a 2-digit number ending in 8. 2. The last digit of the answer is always 4: _ _ _ 4 3. Multiply the first digit by 6 and add 6 (keep the carry): _ _ X _ 4. Multiply the first digit by the next consecutive number and add the carry: the product is the first two digits: XX _ _.
Example:
1. If the number is 78: 2. The last digit of the answer is 4: _ _ _ 4 3. Multiply the first digit (7) by 6 and add 6 (keep the carry): 7 × 6 = 42, 42 + 6 = 48; the next digit of the answer is 8 (keep carry 4): _ _ 8 4 4. Multiply the first digit (7) by the next number (8) and add the carry (4):7 × 8 = 56, 56 + 4 = 60 (the first two digits): 6 0 _ _ 5. So 78 × 78 = 6084. See the pattern?
1. For 38 × 38 2. The last digit of the answer is 4: _ _ _ 4 3. Multiply the first digit (3) by 6 and add 6 (keep the carry): 3 × 6 = 18, 18 + 6 = 24; the next digit of the answer is 4 (keep carry 2): _ _ 4 4 4. Multiply the first digit (3) by the next number (4) and add the carry (2):3 × 4 = 12, 12 + 2 = 14 (the first two digits): 1 4 _ _ 5. So 38 × 38 = 1444
Learn the pattern, practice other examples, and you will be a whiz at giving these squares. |
posted by marhadi @ 6:21 AM  |
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Name: marhadi
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